Respuesta :
Answer:
- Below is proved that for the set of data described none measure for group B is $1 greater than for group A.
Explanation:
The information for the two groups may be summarized in this way.
- Note that each dot is one student, and that here I use * to represent the dots.
Group A:
- $0: __ (0 dots)
- $1: * * * * * (5 dots)
- $2: * * * * (4 dots)
- $3: * (1 dot)
- $4: __ (0 dots)
- $5: __ (0 dots)
- Total number of dots: 5 + 4 + 1 = 10
- Mode: $1 (the value that is repeated more times, 5 times).
- Mean: [$1 × 5 + $2 × 4 + $3 × 1 ] / 10 = $11 / 10 = $1.1
- Median: [the value of the sixth point - value of the fifth point ] / 2 = [$1 + $2] / 2 = 1.5
- Range: maximum value - minimum value = $3 - $1 = $2
Group B:
- $0: * (1 dot)
- $1: * * * (3 dots)
- $2: * * * (3 dots)
- $3: * * * * (4 dots)
- $4: * (1 dots)
- $5: * * * (3 dots)
- Total number of dots: 1 + 3 + 3 + 4 + 1 + 3) = 15
- Mode: $4 (the most repeated value)
- Mean: [$1 × 3 + $2 × 3 + $3 × 4 + $4 × 1 + $5 × 3 ] / 10 = $40 / 10 = $4
- Median: the value of the eigth point = $3
- Range: maximum value - minimum value = $5 - 0 = $ 5
Differences:
Mode
- Group A: $1
- Group B: $4.
- Hence, difference is $3
Mean:
- Group A: $1.1
- Group B: $4
- Hence, difference is $ 2.9
Median:
- Group A: $1.5
- Group B: $ 3
- Hence, difference is $1.5
Range:
- Group A: $3
- Group B: $5
- Hence, the difference is $5 - $3 = 2
Answer:
basically if i narrow that question down i get that its C.
Step-by-step explanation: