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Two uniformly charged conducting plates are parallel to each other. They each have area A. Plate #1 has a positive charge Q while plate #2 has a charge −3 Q.
Using the superposition principle find the magnitude of the electric field at point P in the gap.
1. E =5Q / εoA
2. E = 4Q/εoA
3. E =3Q/ εoA
4. E =Q/ εoA
5. E =2Q/ εoA

Respuesta :

Answer:5

Explanation:

Given

First Plate has a charge of +Q  and area A

Second Plate has a charge of -3 Q and area A

We Know electric Field due to sheet charge is given by

[tex]E=\frac{Q}{2A\epsilon }[/tex]

Where Q=charge over the Plate

A=Area of plate

[tex]\epsilon [/tex]= Permittivity of free space

Electric Field Due to Positive charge will always be away from it while for negative charge it is towards it.

Net Electric Field at a point between between the Plates is the superimposition of two electric with direction

[tex]E_{net}=\frac{Q}{2A\epsilon }+\frac{3Q}{2A\epsilon }[/tex]

[tex]E_{net}=\frac{2Q}{A\epsilon }[/tex]

Net electric Field is towards the negative charged plate

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