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A girl stands on a moving sidewalk (conveyor belt) that is moving to the right at a speed of 2 m/s relative to the ground. A dog runs on the belt toward the girl at a speed of 8 m/s relative to the belt. What is the speed of the dog relative to the ground?

Respuesta :

Answer:

Explanation:

Given

Speed of elevator is given by [tex]v_{eg}=2\ m/s[/tex]

Dog is running towards the girl with velocity [tex]v=8_{ds}[/tex] w.r.t sidewalk

Therefore velocity of dog w.r.t ground

[tex]v_{ds}=v_{dg}-v_{eg}[/tex]

[tex]v_{dg}=v_{ds}+v_{eg}[/tex]

[tex]v_{dg}=8+2=10\ m/s[/tex]        

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