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A2 kg block is accelerating at the rate of 5 m/s² while being acted on by two forces. One of the forces equals 30 N, 0°. What are the
magnitude and the direction of the other force?

Respuesta :

rafaleo84

Answer:

20 [N], in the opposite direction of the first force.

Explanation:

We know that newton's second law stipulates that the sum of forces on a body must be equal to the product of mass by acceleration.

[tex]SumF = m*a\\30 + F = 2*5\\F = 30 - (2*5)\\F = - 20 [N][/tex]

The negative sign means that the other force acting on the body must be in the opposite direction to the force of 30 [N]

onyebuchinnaji

The magnitude and direction of the second force is -20 N in horizontal direction.

The given parameters;

  • mass of the block, m = 2 kg
  • acceleration of the block, a = 5 m/s²
  • one of the applied forces, F₁ = 30 N, at 0⁰

The magnitude of the second force is calculated as follows;

[tex]\Sigma F = ma\\\\F_1 + F_2 = ma\\\\F_2 = ma- F_1\\\\F_2 = (2\times 5) \ - 30cos(0)\\\\F_2 = 10 - 30\\\\F_2 = -20 \ N[/tex]

Thus, the magnitude and direction of the second force is -20 N in horizontal direction.

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