Answer:
a= 289 m/s²
Explanation:
Given that
mass , m =1 kg
Radius of the path ,R= 1.09 m
The maximum speed ,V= 17 m/s
Lets take the maximum acceleration = a
The radial acceleration is given as
[tex]a= \dfrac{V^2}{R}[/tex]
V=Velocity
R=Radius of the circular path
Now by putting the values in the above equation we get
[tex]a= \dfrac{17^2}{1}\ m/s^2[/tex]
a= 289 m/s²
