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A block with a weight of 3.0 N is at rest on a horizontal surface.A 1.0 N upward force is applied to the block by means of an attached vertical string. What are the (a) magnitude and (b) direction of the force of the block on the horizontal surface?

Respuesta :

Answer:

Explanation:

Given

weight of block [tex]W=3\ N[/tex]

A force is of [tex]F=1 N[/tex] is applied on the block

As 1 N is less than weight of block so block exert  Force less than its weight

[tex]F_{net}=mg-F[/tex]

[tex]F_{net}=3-1=2\ N[/tex]

So Block exert a force of 2 N downward on floor                                                              

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