A body of mass 5 gm is executing s.H.M. About a point with amplitude 10 cm. Its maximum velocity is 100 cm/sec. Its velocity will be 50 cm/sec at a distance.

a. 5
b. 5√2
c. 5√3
d. 10√2

Respuesta :

Answer:

Explanation:

Given

Amplitude [tex]A=10 cm[/tex]

mass of body [tex]m=5 gm[/tex]

maximum velocity [tex]v_{max}=100 cm/s[/tex]

if [tex]x=A\cos (\omega t)[/tex] is the general equation of SHM

where [tex]\omega =natural\ frequency\ of\ oscillation[/tex]

[tex]A=maximum\ amplitude[/tex]

[tex]t=time[/tex]

maximum amplitude is [tex]v_{max}=A\omega [/tex]

[tex]100=10\times \omega [/tex]

[tex]\omega =10 cycle/s[/tex]

and velocity at any instant is given by

[tex]v=\omega \sqrt{A^2-y^2}[/tex]

[tex]50=10\sqrt{10^2-y^2}[/tex]

[tex]5=\sqrt{10^2-y^2}[/tex]

squaring

[tex]25=100-y^2[/tex]

[tex]y^2=75[/tex]

[tex]y=5\sqrt{3}\ cm[/tex]