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A spring (k = 790 N/m) has a length of 48 cm when zero net force is applied to it. What will its length be when 230 N of force is applied to stretch it?
Question 3 options:

3.4 m

0.77 m

3.9 m

0.29 m

Respuesta :

Answer:

0·77 m

Explanation:

Given

Spring constant = k = 790 N/m

Equilibrium length of the spring = 48 cm = 0·48 m

Force applied = 230 N

Let the x m be the length of the spring when 230 N of force is applied on it

Spring force that is acting will be k × (x - 0·48)

Because spring force that is acting will be proportional to length from the equilibrium position

When applied force is 230 N, the spring force will also be equal to 230 N as there will be equilibrium

∴ k × (x - 0·48) = 230

790 × (x - 0·48) = 230

x = (230 ÷ 790) + 0·48

x = 0·29 + 0·48

∴ x = 0·77 m

∴ Length of the spring when 230 N of force is applied to stretch it = 0·77 m

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