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So i've been having some real trouble understanding Trigonometry-sine ratio, and was wondering if anybody could explain to me how to do it? It would be awesome if you could :< i put a problem below thanks if you do, its greatly appreciated

So ive been having some real trouble understanding Trigonometrysine ratio and was wondering if anybody could explain to me how to do it It would be awesome if y class=

Respuesta :

david111602

Answer:

15/17

Step-by-step explanation:

sin is opposite over hypotenuse and in this example you find the opposite of angle C which is 15 and put it over the hypotenuse (diagonal line) which is 17

Answer:

15/17

Step-by-step explanation:

SOHCAHTOA

So Sin is Opp/hyp or opposite over hypotenuse. 15 is opposite to C and 17 is the hypotenuse.

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