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If a vehicle averages 27 ​mi/h on a 162 mi trip and then returns over the same 162 mi at the rate of 81 mi divided by h mi/h​, what is your average speed for the​ trip? Give reasons for your answer. Write the integral that represents this information.

Respuesta :

obasola1

Answer:    1.average speed=40.5mi/hr

2.∫vdt=.∫ds

Explanation:

for the first trip= speed=distance/time

v1=s/t

27=162/t

t1=6h

for the second trip

v=s/t

81=162/t2

t2=2h

average speed=s1+s2/(t1+t2)

162+162/(2+6)

average speed=40.5mi/hr

v=ds/dt

vdt=ds..........1

integrating both sides

∫vdt=.∫ds

s=v[tex]v^{2} /2 +C    \\ t_{0} =0  and t_{F}= 8\\[/tex]

s=8^2/2-0^2/2

s=32+C

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