Answer:
Remember, for solve the quadratic equation
[tex]ax^2+bx+c=0[/tex]
we use the quadratic formula
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
We have the equation [tex]3x+8=9x^2[/tex] since a must be 9 then we pass the entire left side of the equation to the right side. We get the equation:
[tex]3x+8=9x^2\\8=9x^2-3x\\0=9x^2-3x-8[/tex]
Then, observe that a=9 and b=-3
