Answer:
The base must be ethylamine.
Explanation:
The pH of solution of a weak base gives us an idea about the Kb of the base.
[tex]pOH=14-pH[/tex]
[tex]pOH=14-11.79=2.21[/tex]
[tex]pOH=-log[OH^{-}][/tex]
[tex][OH^{-}]=0.0062M[/tex]
The relation between Kb and hydroxide ion concentration is:
[tex]Kb=\frac{[OH^{-}]^{2}}{[base]}[/tex]
[tex]Kb=\frac{0.0062X0.0062}{0.0884}=4.34X10^{-4}[/tex]
Thus the weak base must be ethylamine.
