Respuesta :
Answer:7.56 kJ
Explanation:
mass of first train [tex]m_1=1.50\times 10^5 kg[/tex]
mass of second train [tex]m_2=2\times 10^5 kg[/tex]
velocity of first train [tex]v_1=0.3\hat{i} m/s[/tex]
velocity of second train [tex]v_2=-0.12 \hat{i} m/s[/tex]
conserving momentum
[tex]m_1v_1+m_2v_2=(m_1+m_2)v[/tex]
[tex]v=\frac{m_1v_1+m_2v_2}{m_1+m_2}[/tex]
[tex]v=\frac{.50\times 10^5\times 0.3-2\times 10^5\times 0.12}{(1.5+2)\cdot 10^5}[/tex]
[tex]v=0.06 m/s[/tex]
Energy Lost in Inelastic collision
[tex]=\frac{m_1v_1^2}{2}+\frac{m_2v_2^2}{2}-\frac{(m_1+m_2)v^2}{2}[/tex]
[tex]=\frac{1.50\times 10^5\times 0.3^2}{2}+\frac{2\times 10^5\times (-0.12)^2}{2}-\frac{3.5\times 10^5\times 0.07^2}{2}[/tex]
[tex]=\frac{(0.135+0.0288-0.0126)\times 10^5}{2}[/tex]
[tex]=\frac{0.1512\times 10^5}{2}[/tex]
[tex]=7.56 kJ[/tex]
