Answer:
K' = 1777.777 J
Explanation:
Given that
m = 40 kg
v= 15 m/s
K=1000
Given that kinetic energy(K) varies with mass(m) and velocity(v)
K= C(mv²)
Where
C= Constant
m=mass
v=velocity
When
m = 40 kg ,v= 15 m/s ,K=1000
K= C(mv²)
1000 = C( 40 x 15²)
C=0.111111
When m = 40 kg and v= 20 m/s
K' = C(mv²)
K= 0.1111 x (40 x 20²)
K' = 1777.777 J
Answer:
1777.78 Joules
Explanation:
v = Velocity of object
m = Mass of object
Kinetic energy
[tex]K=\frac{1}{2}mv^2\\\Rightarrow m=\frac{2K}{v^2}\\\Rightarrow m=\frac{2\times 1000}{15^2}[/tex]
The mass of the object is 4.44 kg.
Here the mass remains constant
If v = 20 m/s
[tex]K=\frac{1}{2}mv^2\\\Rightarrow K=\frac{1}{2}\times\frac{2\times 1000}{15^2}\times 20^2\\\Rightarrow K=1777.78\ Joules[/tex]
The kinetic energy of the object when the speed is increased to 20 m/s is 1777.78 Joules
