Suppose that y is directly proportional to x and that y = 10 when x = 3. Complete parts (a) and (b). (a) Find the constant of proportionality k. (b) Use y = kx to find y when x = 6.​

Respuesta :

For this case we have that if "y" varies directly with "x", then it is true that:

[tex]y = kx[/tex]

Where:

k: It is the constant of proportionality

We have according to the data that:

[tex]10 = k (3)[/tex]

We find the value of "k":

[tex]k = \frac {10} {3}[/tex]

Having "k", we find "y" when [tex]x = 6[/tex]:

[tex]y = \frac {10} {3} (6)\\y = \frac {60} {3}\\y = 20[/tex]

ANswer:

[tex]k = \frac {10} {3}\\y = 20[/tex]