Answer:
5.) y = 170t
6.) By finding the common rates (slope) (rise over run or y/x)
7a.) Car two isn't going at the constant speed
7b.) They relate by they would still carry the same factors 40mph(from car#2), and 80mph (from car #4) have a common factor of 40 and 35mph (from car #2) and 70mph (from car #4) would have a common factor of 35)
Step-by-step explanation:
(for #5) "t" would mean time as in for hours and the 170 is considered as "m" in the equation of (y=mt+b) and there isn't a starting point of when the bullet trained have already drove (which would have been the number for "b")
So your equation for this would have been y=170t
(For #6) in order for the table or the relationship to be proportional, there must be a constant slope, so the equation would be (when doing it algebraically)
[tex]\frac{x_{2} -x_{1} }{y_{2} -y_{1} }[/tex] or there is a constant adding (like for example in car 3, the y sections would add by 20 not multiply)
( Or when looking at the table)
for every pair, when you [tex]\frac{y}{x}[/tex] for every pair, it should led you to the same number
so in car 2, everything had the constant speed of 35mph except when dividing [tex]\frac{y}{x}[/tex] for 800/20, it gave us 40mph instead of 800
(For #7a) same thing for #6 but i was using the question from 7a to explain the explanation for #6
(For #7b) (I hope it was easy to understand on what I was talking about)
(Helper's note: I hope it was easy to understand, I tried my best to explain with words [as you can see not good at explaining in words but in numbers haha] )
