At what altitude has the air pressure dropped to 50% (half) of air pressure at sea level (1,013 millibars)?

Atmospheric pressure is around 1,014 millibars (14.7 pounds/inch2) at sea level. At an elevation of 10 km (6 miles or about 30,000 feet), roughly the height of Mt. Everest, pressure drops to 265 millibars. That's less than 30% of the pressure at sea level.

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oladayoademosu oladayoademosu · Answer 2 · 2021-09-28T14:57:07+02:00

The answer to the question At what altitude has the air pressure dropped to 50% (half) of air pressure at sea level (1,013 millibars) is 4.22 km

To find the altitude at which the atmospheric pressure drops to 50% of the air pressure at sea level, we use the equation

P = ρgh where P = pressure at h = 50 % of 1013 mbar = 0.5 × 101300 N/m² = 50650 N/m², ρ = density of air = 1.225 kg/m³ and g = acceleration due to gravity = 9.8 m/s² and h = altitude at 50 % of air pressure at sea level.

Since P = ρgh

making h subject of the formula, we have

h = P/ρg

Substituting the values of the variables into the equation, we have

h = 50650 N/m²/(1.225 kg/m³ × 9.8 m/s²)

h = 50650 N/m²/12.005 kg/m²

h = 4219.08 m

h = 4.21908 km

h ≅ 4.22 km

So, the answer to the question At what altitude has the air pressure dropped to 50% (half) of air pressure at sea level (1,013 millibars) is 4.22 km

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