Answer:
55 min
Explanation:
The missing question is: how long does the trip take?
First of all, we need to find the initial distance covered by Dylan. In the first part, he rides for
[tex]t_1 = 20 min = \frac{1}{3}h[/tex]
at a speed of
v = 15 mph
therefore, the distance he covered is
[tex]d = v t_1 = (15)(\frac{1}{3})=5 mi[/tex]
Then Dylan stopped for a time of
[tex]t_2 = 5 min = \frac{5}{60}=\frac{1}{12}h[/tex]
Finally, on the way back, Dylan covered again this distance but travelling at a new speed of
v = 10 mph
So, the time he took is
[tex]t_3 = \frac{d}{v}=\frac{5}{10}=\frac{1}{2}h = 30 min[/tex]
So, the total time of the trip was
[tex]t=t_1 + t_2 + t_3 = 20 min + 5 min + 30 min = 55 min[/tex]
