Answer:
8.75 m/s^2
Explanation:
initial speed, u = 300 m/s
final speed, v = 400 m/s
distance, h = 4 km = 4000 m
Let a be the acceleration of the plane.
Use third equation of motion
[tex]v^{2}=u^{2}- 2 gh[/tex]
[tex]400^{2}=300^{2}- 2 \times a \times 4000[/tex]
a = 8.75 m/s^2
Thus, the acceleration of the plane is 8.75 m/s^2.
