Respuesta :
The answer to this question would be: 1 5/6
To change a decimal number into fraction, you need to divide the number on the right of decimal point with 1. In this case, the number is 0.83.
This number is hard since .83 doesn't have many factors. To find the answer you can try to multiply the decimal with some number until it close to 1(no decimal left)
0.83* 2= 1.66
0.83* 3= 2.49 ---> close to half, if you find this number, you can try to double it
0.83* 4= 3.32
0.83* 5= 4.15
0.83* 6= 4.98---> close to 1, that means there is high probability that the number can be divided by 6
0.83 would be 4.98/6, but if we assume that the number is 0.8333...... then 0.83 would be 5/6. So, 1.83 would be 1 5/6
To change a decimal number into fraction, you need to divide the number on the right of decimal point with 1. In this case, the number is 0.83.
This number is hard since .83 doesn't have many factors. To find the answer you can try to multiply the decimal with some number until it close to 1(no decimal left)
0.83* 2= 1.66
0.83* 3= 2.49 ---> close to half, if you find this number, you can try to double it
0.83* 4= 3.32
0.83* 5= 4.15
0.83* 6= 4.98---> close to 1, that means there is high probability that the number can be divided by 6
0.83 would be 4.98/6, but if we assume that the number is 0.8333...... then 0.83 would be 5/6. So, 1.83 would be 1 5/6
1.83838383... = 182/99
1.83333333... = 11/6
1.83183183... = 610/333
Further explanation
Firstly , let us learn about types of sequence in mathematics.
Arithmetic Progression is a sequence of numbers in which each of adjacent numbers have a constant difference.
[tex]T_n = a + (n-1)d[/tex]
[tex]S_n = \frac{1}{2}n ( 2a + (n-1)d )[/tex]
Tn = n-th term of the sequence
Sn = sum of the first n numbers of the sequence
a = the initial term of the sequence
d = common difference between adjacent numbers
Geometric Progression is a sequence of numbers in which each of adjacent numbers have a constant ration.
[tex]T_n = a ~ r^{n-1}[/tex]
[tex]S_n = \frac{a( 1 - r^n ) }{1 - r}[/tex]
Tn = n-th term of the sequence
Sn = sum of the first n numbers of the sequence
a = the initial term of the sequence
r = common ratio between adjacent numbers
Let us now tackle the problem!
Since the question is not clearly stated, then let me assume the problem is to convert 1.83838383... as a fraction.
Let :
X = 1.8383838383... = 1.83
100X = 183.83838383... = 183.83
100X - X = 183.83 - 1.83
99X = 182
X = 182 ÷ 99
[tex]\large {\boxed {X = \frac{182}{99} } }[/tex]
If the problem is to convert 1.833333... as a fraction , then :
Let :
X = 1.833333... = 1.83
10X = 18.33333... = 18.3
100X = 183.3333... = 183.3
100X - 10X = 183.3 - 18.3
90X = 165
X = 165 ÷ 90
[tex]\large {\boxed {X = \frac{11}{6} } }[/tex]
If the problem is to convert 1.83183183183... as a fraction , then :
Let :
X = 1.83183183183... = 1.83183
100X = 183.183183... = 183.183
100000X = 183183.183... = 183183.183
100000X - 100X = 183183.183 - 183.183
99900X = 183000
X = 183000 ÷ 99900
[tex]\large {\boxed {X = \frac{610}{333} } }[/tex]
Learn more
- Geometric Series : https://brainly.com/question/4520950
- Arithmetic Progression : https://brainly.com/question/2966265
- Geometric Sequence : https://brainly.com/question/2166405
Answer details
Grade: Middle School
Subject: Mathematics
Chapter: Arithmetic and Geometric Series
Keywords: Arithmetic , Geometric , Series , Sequence , Difference , Term

