Answer:
The spring constant is 45.94 N/m.
Explanation:
Given that,
Length = 50 cm
Mass = 270 g
Stretching the spring = 24 cm
We need to calculate the spring constant
Using formula of energy
The change in potential energy equal to the change in kinetic energy.
[tex]mgh=\dfrac{1}{2}kx^2[/tex]
Put the value into the formula
[tex]270\times10^{-3}\times9.8\times50\times10^{-2}=\dfrac{1}{2}\times k\times(24\times10^{-2})^2[/tex]
[tex]k=\dfrac{2\times270\times10^{-3}\times9.8\times50\times10^{-2}}{(24\times10^{-2})^2}[/tex]
[tex]k=45.94\ N/m[/tex]
Hence, The spring constant is 45.94 N/m.
