Respuesta :
Answer:
The c++ program to implement the while loop is given below.
#include <iostream>
using namespace std;
int main() {
// declaration of integer variables
int k, n, total;
// initialization of integer variables
k=1, n=4, total=0;
// loop executed till value of k becomes equal to value of n
while( k <= n ){
// cube of every integer is added to the variable total
total = total + ( k * k * k );
// value of k is incremented to go to the next number
k = k + 1 ;
}
return 0;
}
Explanation:
The program begins with the declaration of integer variables.
int k, n, total;
This is followed by initialization of these variables.
k=1, n=4, total=0;
The while loop runs over the variable k which is initialized to 1. The loop runs till value of k reaches the value of integer n.
First, cube of k is computed and added to the variable total.
After first execution of the loop, total is initialized to the cube of 1.
Next, value of variable k is incremented by 1 so that k is initialized to next integer.
After first execution of the loop, k is incremented from 1 to 2.
while( k <= n )
{
total = total + ( k * k * k );
k = k + 1 ;
}
When the value of k reaches the value of integer n, the cube of n is calculated and added to the variable, total.
When k is incremented, it becomes more than n and hence, loop gets terminated.
As the return type of main is int, the program terminates with the statement shown below.
return 0;
No output is displayed as it is not mentioned in the question.
No user input is taken as it is mentioned that integer variables are already initialized.
