A wave has a frequency of 0.5 kHz and two particles with a phase difference of \pi /3 are 1.5 cm apart. Calculate: the time period of the wave.

Respuesta :

Answer:

The time period of the wave is 0.002 sec.

Explanation:

Given that,

Frequency = 0.5 kHz

Phase difference [tex]\phi=\dfrac{\pi}{3}[/tex]

Path difference = 1.5 cm

We need to calculate the time period

Using formula of time period

The frequency is the reciprocal of time period.

[tex]f =\dfrac{1}{T}[/tex]

[tex]T=\dfrac{1}{f}[/tex]

Where, f = frequency

Put the value into the formula

[tex]T=\dfrac{1}{0.5\times10^{3}}[/tex]

[tex]T=0.002\ sec[/tex]

Hence, The time period of the wave is 0.002 sec.