Answer:
Force constant, K = 101.49 N/m
Explanation:
It is given that,
Mass, m = 30.6 kg
Time period of oscillation, T = 3.45 s
We need to find the force constant of the spring. The time period of the spring is given by :
[tex]T=2\pi\sqrt{\dfrac{m}{K}}[/tex]
[tex]K=\dfrac{4\pi^2m}{T^2}[/tex]
[tex]K=\dfrac{4\pi^2\times 30.6\ kg}{(3.45\ s)^2}[/tex]
K = 101.49 N/m
So, the force constant of the spring is 101.49 N/m. Hence, this is the required solution.
