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A 1m length of wire carrying a current of 7A lies on a horizontal table with a rectangular top of dimensions 0.6m x 0.8m. The ends of the wire are attached to opposite ends of a diagonal of the rectangle. A vertical magnetic field of 0.IT is present. What magnetic force acts on this segment of wire? a) 0.7N b) 0.98N c) 7N d) zero

Respuesta :

Answer:

F = 0.7 N

Explanation:

As we know that the wire touch the ends of the diagonal of the rectangle

so here the length of the wire is given as

[tex]L = \sqrt{x^2 + y^2}[/tex]

[tex]L = \sqrt{0.6^2 + 0.8^2}[/tex]

[tex]L = 1 m[/tex]

now force due to magnetic field on current carrying wire is given as

[tex]F = iLB[/tex]

now we have

[tex]F = (7)(1)(0.1)[/tex]

[tex]F = 0.7 N[/tex]

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