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A student measured the density of gold to be 19.1 g/cm^3. The accepted value of the density of gold is 19.3 g/cm^3. What is the percent error of the student's measurement?

A. 0.20%
B. 1.71%
C. 1.04%
D. 1.39%

Respuesta :

Answer:

C. 1.04%

Explanation:

The following information has been provided;

Actual density of gold; 19.3 g/cm^3

Observed/measured density of gold; 19.1 g/cm^3

The formula for percent error is given as;

((actual value - observed value)/actual value)) * 100

[tex]\frac{19.3-19.1}{19.3}*100=1.0363[/tex]

The percent error of the student's measurement is thus 1.04%

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