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An astronaut drops a rock into a crater on the moon. The distance, d(t), in meters, the rock travels after t seconds can be modeled by d(t)=0.8t^2. What is the average speed, in meters per second, of the rock between 5 and 10 seconds after it was dropped?

Respuesta :

Plug in 5 and 10 to the equation.

For the first one would be d(5) = 0.8(5)^2

Multiply the equation d(5) = 4^2

Then you just multiply the exponent the would be d(5) = 10

The second one, you just do the same thing and the answer would be d(10) = 64

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