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The standard form of the equation of a circle is (x−4)2+(y−2)2=9. What is the general form of the equation?

x2+y2+8x+4y−29=0

x2+y2−8x−4y−29=0

x2+y2−8x−4y+11=0

x2+y2+8x+4y+11=0

Respuesta :

calculista

Answer:

[tex]x^{2}+y^{2}-8x-4y+11=0[/tex]

Step-by-step explanation:

we have

[tex](x-4)^{2}+(y-2)^{2}=9[/tex]

The general equation of the circle is equal to

[tex]x^{2}+y^{2}+Ax+By+C=0[/tex]

Convert the standard form to a general form

[tex](x-4)^{2}+(y-2)^{2}=9\\ \\(x^{2} -8x+16)+(y^{2}-4y+4)=9\\ \\x^{2}+y^{2}-8x-4y+20-9=0\\ \\x^{2}+y^{2}-8x-4y+11=0[/tex]

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