Respuesta :
With standard pressure there is a set list of values. (at STP), most common is 760torr. So whenever you see "at STP" or "at standard temperature pressure" you will use 760torr for pressure. Same thing goes with temperature, if you're not given temp and it says at STP you will use 273K.
For this problem:
You will be using the combined gas law:
(Pressure 1) x (Volume 1) / (Temp. 1) = (Pressure 2) x (Volume 2) / (Temp. 2)
(760torr) x (5.63L) / (287K) = (?) (9.21L) / (287K)
Pressure 2 = 465torr
*Hope this clarifies STP for you! :)
Considering the Boyle's law, the pressure of the gas without a change in temperature will be 0.61 atm.
As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them fewer times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:
"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"
So if the pressure increases, the volume decreases, while if the pressure decreases, the volume increases.
Boyle's law is expressed mathematically as:
P×V= k
Considering that the initial conditions 1 are modified until reaching the final conditions 2, it is satisfied:
P1×V1 = P2×V2
In this case, you know:
- P1= 1 atm. The STP conditions refer to the standard temperature and pressure. Pressure values at 1 atmosphere is used and are reference values for gases.
- V1= 5.63 L
- P2= ?
- V2= 9.21 L
Replacing in Boyle's law:
1 atm× 5.63 L= P2× 9.21 L
Solving:
[tex]P2=\frac{1 atmx 5.63 L}{9.21 L}[/tex]
Finally, the pressure of the gas without a change in temperature will be 0.61 atm.
Learn more:
- brainly.com/question/4147359?referrer=searchResults
- https://brainly.com/question/12787320
