Answer:
6.4 kilometer
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Step-by-step explanation:
See the attached figure.
Let Julian starts from point O (0,0)
Julian jogs 2 kilometers east ⇒ arrived to point A (2,0)
4 kilometers north ⇒ arrived to point B (2,4)
and then 7 kilometers west ⇒ arrived to point C (-5,4)
How far is Julian from his starting position?
So, it is required to find the distance OC
From the graph OC = [tex]\sqrt{(-5)^2+(4)^2}=\sqrt{25+16} =\sqrt{41} =6.403[/tex]
So, the distance from his starting position ≈ 6.4 km (to the nearest tenth of a kilometer)
