Respuesta :
Answer: No, She is not right.
Step-by-step explanation:
First question:
Initial number of bison = 550
After increasing 10% than the initial number of bison, the new number of bison after one year= Initial number of bison + 10 % of the initial number of bison
= [tex]110\% \text{ of the initial number of bison}[/tex]
= [tex]110\% \text{ of }550[/tex]
= [tex]\frac{110\times 550}{100}[/tex]
= [tex]\frac{60500}{100}[/tex]
= [tex]605[/tex]
Second question:
Let Initial number of bison = x
After decreasing 10% than the initial number of bison, the new number of bison after one year= Initial number of bison - 10 % f the initial number of bison
= [tex]90\% \text{ of the initial number of bison}[/tex]
= [tex]90\% \text{ of } x[/tex]
= [tex]\frac{90\times x}{100}[/tex]
= [tex]\frac{9x}{10}[/tex]
According to the question,
[tex]\frac{9x}{10}=550[/tex]
[tex]x=\frac{5500}{9}=611.11\approx 611[/tex]
Since, 605 ≠ 611
Therefore, Both questions have different answer.
⇒ Noah is not correct.