Write the following equation in standard form then solve. 6q^2-2q=5q^2-5q+28

Answer:
q = -7, q = 4
Step-by-step explanation:
subtract 5q² - 5q + 28 from both sides to obtain standard form
q² + 3q - 28 = 0 ← in standard form
(q + 7)(q - 4) = 0 ← in factored form
equate each factor to zero and solve for q
q + 7 = 0 ⇒ q = - 7
q - 4 = 0 ⇒ q = 4