Answer:
D.
[tex]y=-\pi[/tex]
Step-by-step explanation:
we are given
[tex]f(t)=\frac{1}{2}sec(t+2)-\pi[/tex]
we can use general form of trig
[tex]y=Asec(Bt+C)+D[/tex]
where
middle line is y=D
now, we can compare them and find D
and we get
[tex]D=-\pi[/tex]
So, middle line is
[tex]y=-\pi[/tex]
