celcavitt
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If a pendulum swings with a period of 1.00 s and has a length of 0.250 m, calculate the magnitude of the acceleration due to gravity.

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remotecontrolbrain

Answer:

The magnitude of g is 9.870 m/s^2

Explanation:

Use the formula tying the period to the length of a pendulum for small amplitudes[tex]T=2\pi\sqrt{\frac{L}{g}}\implies g = \frac{4\pi^2 }{T^2}L=9.870\frac{m}{s^2}[/tex]: