Answer : The concentration can be expressed as, 1.99 M, or 15.1(m/m)%, or 18(m/v)%
Solution : Given,
Volume of solution = 0.5 L = 500 ml (1 L = 1000 ml)
Mass of solution = 596 g
Mass of oxalic acid, (solute) = 90 g
Molar mass of oxalic acid = 90.03 g/mole
First we have to calculate the concentration in terms of M(molarity).
Molarity : Molarity is defined as the number of moles of solute present in one liter of solution.
Formula used : [tex]M=\frac{w_{solute}}{M_{solute}\times V_s}[/tex]
where,
M = molarity of solution
[tex]w_{solute}[/tex] = mass of solute(oxalic acid)
[tex]M_{solute}[/tex] = molar mass of solute(oxalic acid)
[tex]V_s[/tex] = volume of solution(in liters)
Now put all the given values in this formula, we get
[tex]M=\frac{90g}{90.03g/mole\times 0.5L}=1.99mole/L=1.99M[/tex]
Now we have to calculate the concentration in terms of (m/m)%
(m/m)% : It is defined as the mass of solute present in mass of solution in grams.
Formula used : [tex](m/m)\%=\frac{w_{solute}}{w_s}\times 100[/tex]
where,
[tex]w_s[/tex] = mass of solution
[tex](m/m)\%=\frac{90g}{596g}\times 100=15.1%[/tex]
Now we have to calculate the concentration in terms of (m/v)%
(m/v)% : It is defined as the mass of solute present in one milliliter of solution.
Formula used : [tex](m/v)\%=\frac{w_{solute}}{V_s}\times 100[/tex]
where,
[tex]w_s[/tex] = mass of solution
[tex](m/m)\%=\frac{90g}{500ml}\times 100=18%[/tex]
