Respuesta :
Answer:
Option B is correct.
Weight of a bowling ball is 5.24 Ib
Step-by-step explanation:
Assume: The shape of the bowling ball is perfectly spherical.
Given:
Radius of a bowling ball= 5 inches (r) .
One cubic inch weighs [tex]\frac{1}{100}[/tex]th of a pound.
Density of a bowling ball = [tex]\frac{1}{100} Ibs/in^3[/tex]
Volume of sphere is given by:
[tex]V = \frac{4}{3} \pi r^3[/tex] where V is the volume and r is the radius of the sphere.
Substitute the value of r =5 and [tex]\pi = 3.14[/tex] in above we get;
[tex]V = \frac{4}{3} \cdot 3.14 \cdot 5^3 =\frac{4}{3} \cdot 3.14 \cdot 125[/tex]
Simplify:
[tex]V = 523.3333... in^3[/tex]
To find the weight of a bowling ball:
[tex]Weight = Volume \times Density[/tex]
Then;
[tex]Weight = 523.33333.. \times \frac{1}{100} =\frac{523.3333..}{100} = 5.2333...[/tex]
Therefore, the weight of a bowling ball ≈ 5.24 Ib
Answer:
The weight of a bowling ball is 5.24 pounds.
Option (B) is correct.
Step-by-step explanation:
Formula
[tex]Volume\ of\ a\ sphere = \frac{4}{3}\pi\ r^{3}[/tex]
Where r is the radius of a sphere.
As given
The radius of the ball is 5 in.
As the shape of the ball is spherical .
Thus
[tex]Volume\ of\ a\ ball = \frac{4}{3}\pi\ 5^{3}[/tex]
[tex]\pi = \frac{22}{7}[/tex]
Thus
[tex]Volume\ of\ a\ ball = \frac{4\times 22\times 5\times\ 5\times 5}{3\times 7}[/tex]
[tex]Volume\ of\ a\ ball = \frac{11000}{21}[/tex]
Volume of a ball = 523.8 in³ (Approx)
As
[tex]1\ in^{3} = \frac{1}{100}\ pound[/tex]
Thus
Convert 523.8 in³ into pounds.
[tex]523.8\ in^{3} = \frac{523.8}{100}\ pound[/tex]
[tex]523.8\ in^{3} = 5.24\ pound\ (Approx)[/tex]
Therefore the weight of a bowling ball is 5.24 pounds.
Therefore Option (B) is correct.
