Respuesta :
force=mass times acceleration
the person exerts a constant downward force of 9.8*65=637N
in order for the elevator to accelerate upward at 1.2m/s^2, it has to provide a force of 1.2*65=78N
the total force needed is the sum of those 2 or 637+78 or 715N upward
part 2
elevator accelerates downards
so that will be the difference between the 2 forces or 637-78 or 559N upward
Part A
The upward force exerted by the floor of the elevator on the passenger is 715N
Part B
The upward force exerted by the floor of the elevator on the passenger when the elevator accelerates downwards is 559N
From the question,
An elevator accelerates upward at 1.2 m/s²
To determine the upward force exerted by the floor of the elevator on a(n) 65 kg passenger,
When an elevator is accelerating upwards
The force exerted by the floor on a passenger in the elevator is given by
F = m(g + a)
Where F is the force
m is the mass
a is the acceleration of the elevator
g is the acceleration of gravity
From the question
m = 65 kg
a = 1.2 m/s²
g = 9.8 m/s²
Putting these values into the equation, we get
F = m(g + a)
F = 65(9.8 + 1.2)
F = 65 × 11
F = 715N
Hence, the upward force exerted by the floor of the elevator on the passenger is 715N
Part 2
To determine the upward force exerted by the floor of the elevator on the passenger when the elevator accelerates downwards,
When an elevator is accelerating downwards
The force exerted by the floor on a passenger in the elevator is given by
F = m(g - a)
Using the same parameters as above
F = m(g - a)
F = 65(9.8 - 1.2)
F = 65 × 8.6
F = 559N
Hence, the upward force exerted by the floor of the elevator on the passenger when the elevator accelerates downwards is 559N
Learn more here: https://brainly.com/question/13442845
