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The floor of a rectangular deck has a length that is 6 feet more than it’s width, x. Hakeem is building the deck and decided to increase both dimensions by 3 feet. What is the new area, D, of the floor of the deck?

A. x^2 + 12x + 27
B. x^2 + 9x + 18
C. x^2 + 9x
D. x^2 + 6x

Respuesta :

Iqta

The correct Answer is A. x^2 + 12x + 27


Width of floor = w = x

Length of floor = l = x + 6

New dimesions are increase by three so our

W = x + 3

L = x + 6 + 3  =>   L = x + 9

As we know that Area = width*length so

area = W * L

        = (x + 3)*(x + 9)

        = x∧2 + 9x + 3x + 27

        = x∧2 + 12x + 27

Which is our option A.

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