Answer: R' = [tex](3\frac{1}{3} ,1\frac{2}{3})[/tex], S' = [tex](3\frac{1}{3} ,-3\frac{1}{3})[/tex], T' = [tex](-1\frac{2}{3} ,-3\frac{1}{3})[/tex]
Step-by-step explanation:
R = (2, 1) ⇒ R' = [tex](\frac{5}{3})2 , (\frac{5}{3})1 = (\frac{10}{3} , \frac{5}{3})[/tex]
S = (2, -2) ⇒ S' = [tex](\frac{5}{3})2 , (\frac{5}{3})(-2) = (\frac{10}{3} , \frac{-10}{3})[/tex]
T = (-1, -2) ⇒ T' = [tex](\frac{5}{3})(-1) , (\frac{5}{3})(-2) = (\frac{-5}{3} , \frac{-10}{3})[/tex]
Plot the coordinates.
