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ABC below is a right triangle where the measure of AB is 6 units and the measure of ∠A is 50°. What would the area of the triangle be?

A. 18sin50°
B. 18tan50°
C. 6sin50°
D. 36sin50°

ABC below is a right triangle where the measure of AB is 6 units and the measure of A is 50 What would the area of the triangle be A 18sin50 B 18tan50 C 6sin50 class=

Respuesta :

B. is the thing dear friend

Answer:

18 tan 50

Option B

Step-by-step explanation:

Given is a picture of triangle ABC.

The triangle is right angled at B.

AB =6 and angle A = 50

Using trig ratios we have

[tex]\frac{AB}{AC} =\frac{6}{y} =cos50[/tex] where y is length of hypotenuse = AC

Solving y = 6sec 50

Area of triangle = [tex]\frac{1}{2} (AB)(AC) sin 50[/tex]

=[tex]\frac{1}{2} (6)(6sec50)(sin50)\\= 18 tan 50[/tex]

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