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To rent a certain meeting room, a college charges a reservation fee of $19 and an additional fee of $6 per hour. The chemistry club wants to spend less than $91 on renting a room. What are the possible numbers of hours the chemistry club could rent the meeting room? Use t for the number of hours. Write your answer as an inequality solved for t.

Respuesta :

Since t = time, we can guess and check to find what is the maximum number of hours the chemistry club can spend in the room. Lets try 7 hours. After solving you would get, yes seven hours does fulfill their requirements. This means that they can spend 1,2,3,4,5,6,7 hours in the room. Lets try 8 hours. After you solve you get, no eight hours does not fulfill the requirements. So now we can write the inequality: t < 8. Their are 7 possible hours they can rent the room.
gustanika
First, we have to write an inequality expression for the problem
reservation fee + additional fee should be less than $91, we could write it as
19 + 6t < 91

Second, solve the inequality
19 + 6t < 91

substract 19 from both side
19 - 19 + 6t < 91 - 19
6t < 72

divide both side by 6
[tex] \dfrac{6t}{6} \ \textless \ \dfrac{72}{6} [/tex]
t < 12

The possible numbers of hours should be less than 12. That means they could rent for 11 hours or less.

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