Respuesta :
Use the Pythagprean theorem:
[tex]c^2=a^2+b^2[/tex]
We have:
[tex]a=9;\ c=13[/tex]
Substitute:
[tex]9^2+b^2=13^2\\\\81+b^2=169\ \ \ |-81\\\\b^2=88\to b=\sqrt{88}\\\\b=\sqrt{4\cdot22}\\\\Answer:\ b=2\sqrt{22}\approx9.38[/tex]
[tex]c^2=a^2+b^2[/tex]
We have:
[tex]a=9;\ c=13[/tex]
Substitute:
[tex]9^2+b^2=13^2\\\\81+b^2=169\ \ \ |-81\\\\b^2=88\to b=\sqrt{88}\\\\b=\sqrt{4\cdot22}\\\\Answer:\ b=2\sqrt{22}\approx9.38[/tex]
Hey there! :)
You have to use the Pythagorean Theorem: a² + b² = c²
a² + b² = c² → c² - a² = b²
c = 13
13² = 13 × 13 = 169
a = 9
9² = 9 × 9 = 81
169 - 81 = 88
√88 = 9.38
b = 9.38
Hope this helps :)
You have to use the Pythagorean Theorem: a² + b² = c²
a² + b² = c² → c² - a² = b²
c = 13
13² = 13 × 13 = 169
a = 9
9² = 9 × 9 = 81
169 - 81 = 88
√88 = 9.38
b = 9.38
Hope this helps :)