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The length of a rectangular field is represented by the expression 14x-3x^2+2yThe width of the field is represented by the expression 5x-7x^2+7y How much greater is the length of the field than the width?

Respuesta :

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[tex](14x-3x^2+2y)-(5x-7x^2+7y)\\\\=14x-3x^2+2y-5x+7x^2-7y\\\\=-3x^2+7x^2+14x-5x+2y-7y\\\\=4x^2+9x-5y[/tex]

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