Find the derivative of y=5x² sec⁻¹(2x-3).

a. y'=10x· sec⁻¹(2x-3)+ 10x²/|2x-3|√(4x²-12x+8)
b. y'= 20x²/|2x-3|√(4x²-12x+8)
c. y'=10x· sec⁻¹(2x-3)+ 10x²/|2x-3|√(-4x²-12x+8)
d. y'=10x· sec⁻¹(2x-3)+ 10x/|2x-3|√(4x²-12x+8)